If 250 mL of a 0.50 M NaCl solution is diluted to 840 mL, what is the molarity of the resulting solution?

A0.15 M
B6.7 M
C0.60 M
D1.7 M
E0.0025 M

Verified Answer :


Convert all the mL to L first, .25 L and .84 L  (.25) (.5) = (.84) (x) solve... I got .148809524, round to one sig fig (i think) would be .1 M

Answer: a) 0.15 M

Explanation:

According to the dilution law,

\(M_1V_1=M_2V_2\)

where,

\(M_1\) = molarity of stock solution = 0.50 M

\(V_1\) = volume of stock solution = 250 ml

\(M_2\) = molarity of diluted solution = ?

\(V_2\) = volume of diluted solution = 840 ml

Putting in the values, we get:

\(0.50M\times 250=M_2\times 840\)

\(M_2=0.15\)

Therefore, the molarity of the resulting solution is 0.15 M