Answered

How many moles of silver (Ag) are present in a sample of 3.8 × 1024 atoms Ag?


Select one:

A1.6 mol Ag
B2.3 mol Ag
C6.3 mol Ag
D22.8 mol Ag

Verified Answer :


1 mol=6.022 x 10²³ atoms.

1 mol-----------------------------6.022 10²³ atoms
   x--------------------------------3.8 10²⁴ atoms

x=(1 mol 3.8 10²⁴ atoms) / 6.022*10²³ atoms=6.3 moles of Ag,

Answer: C. 6.3 mol Ag

Answer : The correct option is, (C) 6.3 mole Ag

Explanation : Given,

Number of atoms of Ag = \(3.8\times 10^{24}\)

As we know that, 1 mole contains \(6.022\times 10^{23}\) number of atoms.

As, \(6.022\times 10^{23}\) number Ag atoms present in 1 mole of Ag

So, \(3.8\times 10^{24}\) number Ag atoms present in \(\frac{3.8\times 10^{24}}{6.022\times 10^{23}}=6.3\) mole of Ag

Therefore, the number of moles of Ag present are, 6.3 moles

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