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AnalisaCollaco359
AnalisaCollaco359 AnalisaCollaco359
  • 11-09-2014
  • Physics
Answered

A balloon holds 20.0 liters of helium at 10.0°C. If the temperature increases to 50.0°C, and the pressure does

not change, what will be the new volume of the balloon?

Verified Answer :

MaciekMind MaciekMind
  • 11-09-2014

Volum at the beginning: \(V_{1}=10\)
Volum at the end: 
\(V_{2}=V_{1}*(1+ \alpha* (t_{2}-t_{1}))\)
\(t_{2}-t_{1}=50-10=40\)
α for helium = \(0,003658\frac{1}{C}\)
As the result you get:
\(V_{2}=20*(1+0,003658*40)=22,9264 l\)
Final volume of the balloon is 22,9264 liters.

(Only if it doesn't explode during being heated ;) just a joke)

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