a company uses two vans to transport workers from a free parking lot to the workplace between 7:00 and 9:00 am . one van has 6 more seats than the other. the smaller van makes two trips every morning while the larger one makes only one trip. the two vans can transport 57 people , maximum. let X be the seats in the small van and y the seats in the large van . how many seats does the larger van have?
y - x = 6
y + 2x = 57
2y - 2x =12
y + 2x = 57
∴3y = 69
y = 23
23 - x = 6
-x = -17
x =17
large van = 23
small van = 17
x is the seats in the small van.
y is the seats in the large van = (x + 6). Since the large has 6 more seats.
Since the 2 vans can transport 57 people.
Small van makes 2 trips = 2x.
Large van makes one trip = (x + 6).
2x + (x +6) = 57
2x + x + 6 = 57
3x + 6 = 57
3x = 57 -6
3x = 51
x = 51/3
x = 17.
The larger van has (x + 6) = (17 + 6) = 23.
The larger van has 23 seats.