Verified Answer :

slevo

sin\(x\)=\(\frac{opposite}{hypotenuse}\) =\(\frac{ \sqrt{2} }{2}\)
     opposite=\(\sqrt{2}\)
     hypotenuse=2

\(Adjacent^{2}\)+\((\sqrt{2 })^{2 }\)= \(2 ^{2}\)
\(Adjacent^{2}\)+2=4
\(Adjacent^{2}\)=2 
Adjacent=\(\sqrt{2}\)

cos\(x\)=\(\frac{ajc}{hyp}= \frac{ \sqrt{2} }{2}\)
Tan\(x\)=\(\frac{opp}{adj} = \frac{ \sqrt{2} }{ \sqrt{2} }\)