Verified Answer :

carlosego

For this case we have the following functions:
 \(f (x) = 4 - x ^ 2 g (x) = 6x\)
 The first thing we must do is subtract both functions.
 We have then:
 \((g - f) (x) = g (x) - f (x)\)
 Substituting values we have:
 \((g - f) (x) = (6x) - (4 - x ^ 2)\)
 Rewriting we have:
 \((g - f) (x) = x ^ 2 + 6x - 4\)
 Then, we evaluate the function for x = 3.
 We have then:
 \((g - f) (3) = 3 ^ 2 + 6 (3) - 4\)
 Rewriting:
 \((g - f) (3) = 9 + 18 - 4 (g - f) (3) = 23\)
 Answer:
 An expression that is equivalent to (g - f) (3) is:
 \((g - f) (3) = 23\)

Answer:

\((g-f)(3)=23\)

Step-by-step explanation:

Given : \(f(x) = 4 -x^2\) and \(g(x) = 6x\)

To find : The value of \((g -f)(3)\)

Solution :

First we find the value of (g-f)

\((g-f)(x)= g(x)-f(x)\)

\((g-f)(x)=6x-(4-x^2)\)

\((g-f)(x)=6x-4+x^2\)

Now, put the value of x=3

\((g-f)(3)=6(3)-4+(3)^2\)

\((g-f)(3)=18-4+9\)

\((g-f)(3)=23\)

Therefore, \((g-f)(3)=23\)

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