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Four forces are being applied to move an object to the left. Force 1 is pushing to the right at 200 N. Force 2 is pushing to the left at 500 N. Force 3 is pushing to the right at 100 N. Force 4 is pushing to the left at 50 N. What's the net force acting on this object?



A−250 N
B850 N
C0 N
D250 N

Verified Answer :

Four forces are being applied to move an object to the left.
Initial Force = 0N

Force 1 is pushing to the right at 200 N.
Force = 200 N

Force 2 is pushing to the left at 500 N.
Force = 200 - 500 = -300 N

Force 3 is pushing to the right at 100 N.
Force = -300 + 100 = -200 N

Force 4 is pushing to the left at 50 N. 
Force = -200 - 50 = -250 N.

So the final answer is -250 N.
The correct answer is letter A. −250 N .

Answer:

The correct option is A.

Explanation:

Force 1 is pushing to the right at 200 N.

\(F_1= 200N\)

Force 2 is pushing to the left at 500 N.

\(F_2= -500 N\) (negative sign indicates the direction of the force )

Force 3 is pushing to the right at 100 N

\(F_3= 100 N\)

Force 4 is pushing to the left at 50 N

\(F_4= -50 N\) (negative sign indicates the direction of the force )

Net force on the object: \(F_1+F_2+F_3+F_4\)

\(=200N +(-500N) + 100 N + (-50 N) = -250 N\)

-250 N the net force acting on this object.

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