Answer:
\(f^{-1}(x)=9x-18\)
Step-by-step explanation:
we have
\(f(x)=\frac{1}{9}x+2\)
Let
\(y=f(x)\)
\(y=\frac{1}{9}x+2\)
Exchange variables x for y and y for x
\(x=\frac{1}{9}y+2\)
Isolate the variable y
\(x-2=\frac{1}{9}y\)
\(y=9(x-2)\)
\(y=9x-18\)
Let
\(f^{-1}(x)=y\)
\(f^{-1}(x)=9x-18\) -------> inverse function
