A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth, is atm.

Verified Answer :

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth, is atm.

The correct answer to the question is : 1.9 atm.

EXPLANATION:

Let us consider the pressure, volume and temperature of a gas are denoted as P,V and T respectively.

Initial condition :                                                   Final condition:

\(P_{1} = 1.9\ atm\)                                      \(P_{2} =\ ?\)

\(V_{1} =\ 12.8\ L\)                                       \(V_{2} =\ 9.9\ L\)

\(T_{1}=\ 365\ K\)                                        \(T_{2} =\ 285\ K\)

From combined equation of gas, we know that-

                           \(\frac{P_{1}V_{1}}{T_{1} } =\ \frac{P_{2}V_{2}}{T_{2}}\)

                        ⇒ \(P_{2} =\ \frac{P_{1}V_{1}}{T_{1} } \times \frac{T_{2} }{V_{2} }\)

                                 \(=\ \frac{1.9\times 12.8}{365}\times \frac{285}{9.9}\ atm\)

                                 \(=\ 1.91814\ atm\)

                                 \(=\ 1.9\ atm\)              [ans]

Hence, the final pressure is 1.9 atm.