Verified Answer :

SoulCollector

I'm assuming you know binomials, trinomials, and the like. So, make the equation equal to zero.
Once you do you'll get,
4x^2 - 12x - 7 = 0.

Now, unfactor into binomials...
(2x+1) (2x-7) = 0.

Solve for both x's.
2x+1=0
2x-7=0

x= -1/2
x= 7/2

So, x is equal to -1/2 and 7/2.
Good luck!

Solve for x: \(4x^{2} -12x = 7\)
Lets set = 0

\(4 x^{2} - 12 - 7 = 0\)

Now, let's solve this problem by factoring
In your problem you need those 2 factor which multiply to be 28 and add up to -12 because 4 * 7 = 28 

\(4 x^{2} + 2x - 14x -7 = 0 2x ( 2x + 1 ) - 7 ( 2x + 1 ) = 0 (2x - 7 ) ( 2x + 1 ) = 0\)
so now, lets set both the equations for 0.
\(2x - 7 = 0\)
\(2x = 7 x = 7/2\)

and  \(2x + 1 = 0 2x = -1 x= -1/2\) 



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