LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 243. What is the value of x?
According to the feature of midsegment.:
LM =(AB + DC)/2
LM = 4x + 3.
AB= x + 8.
DC = 243.
4x+3=(x+8+243)/2
8x+6=x+251
7x=245
x=35 - the answer.
Answer:
x=35
Step-by-step explanation:
Given ia a trapezoid ABCD with bases AB and CD
Mid segment is LM
AB=x+8
CD =243
LM = mid segment = average of two bases
Hence
LM = \(\frac{x+8+243}{2} =\frac{x+251}{2}\)
Equate this to given LM value
\(\frac{x+251}{2} =4x+3\\x+251=8x+6\\7x=245\\x=35\)
Hence answer is
x=35