Answered

A particular circle in the standard (x,y) coordinate

plane has an equation of (x − 5)2 + y2 = 38. What are

the radius of the circle, in coordinate units, and the

coordinates of the center of the circle?

Verified Answer :

superkoopasirf

For any circle with Cartesian equation
\((x-a)^2 + (y-b)^2 = r^2\),
we have that the centre of the circle is \((a,b)\), and the radius of the circle is \(r\).

So in the case that 
\((x-5)^2 + y^2 = 38\),
we essentially have that
\(a = 5, b = 0, r^2 = 38\).

So the centre of the circle is \((5,0)\), and the radius is \(\sqrt{38}\).

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