Solve for x:3x^2-5x=2
\(3{ x }^{ 2 }-5x=2\\ \\ 3{ x }^{ 2 }-5x-2=0\\ \\ \left( 3x+1 \right) \left( x-2 \right) =0\\ \\ \therefore \quad x=2\\ \\ \therefore \quad x=-\frac { 1 }{ 3 }\)
