Answer:
Only 2 factors have exactly two terms i.e, (x+4)(y+4)
Step-by-step explanation:
Given : Expression \(8(x+4)(y+4)(z^2+4z+7)\)
To find : How many factors in the expression have exactly two terms?
Solution :
Expression \(8(x+4)(y+4)(z^2+4z+7)\) cannot be further factorized.
Now, We count the terms in each factor.
1) Factor- 8
Only 1 term i.e, 8 itself.
2) Factor- x+4
Two terms .i.e., x and 4
3) Factor- y+4
Two terms .i.e., y and 4
4) Factor- \(z^2+4z+7\)
Three terms .i.e., \(z^2\), 4z and 7.
Therefore, Only 2 factors have exactly two terms i.e, (x+4)(y+4).
