Answer:
\(\ln(2981)=4x\)
Step-by-step explanation:
The given equation is \(e^{4x}\approx2981\)
We can use the relation between logarithmic and exponential function.
\(\text{If }y=b^x\text{ then }x=\log_b(y)\)
Here,
b = e
x = 4x
y = 2981
Thus, using the above relation, we can write
\(e^{4x}\approx2981\\\\\log_e(2981)=4x\)
We know \(\log_e(2981)=\ln(2981)\)
Hence, we have
\(e^{4x}\approx2981\\\\\ln(2981)=4x\)
