find the slope of the line 8x-4y=8\
You first have to put 8x-4y=8 into y=mx+b So -4y=8x+8You have to get y alone so you divide each side by -4 y=-2x-2the slope is -2
8x - 4y = 8. Change to form y = mx + c. Where m = slope-4y = -8x + 8. Divide both sides by 4.-4y/-4 = (-8x + 8)/-4 y = 2x - 2. Compare to y = mx + c.Slope, m = 2.