In a series circuit, the voltage across the circuit is always equal to

Athe voltage across one of the bulbs.
Bthe sum of the voltages across each bulb.
Chalf the sum of the voltages across each bulb.
Dtwo times the sum of the voltages across each bulb.

Bthe sum of the voltages across each bulb.

This is unlike parallel circuit where the voltage across the circuit is the same as across each resistor or bulb.

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aristocles aristocles · Answer 2 · 2019-07-19T22:24:55-04:00

Answer:

b. the sum of the voltages across each bulb.

Explanation:

As we know that the total voltage across the given series circuit will give some current to the circuit

The current will remain the same in the circuit in all the resistors.

So here we will have voltage across each resistor given by

$V_1 = i R_1$

$V_2 = i R_2$

$V_3 = i R_3$

and so on

so here for total voltage across all the resistors we can say

$V = V_1 + V_2 + V_3 + ........$

so correct answer will be

b. the sum of the voltages across each bulb.

In a series circuit, the voltage across the circuit is always equal to Athe voltage across one of the bulbs.Bthe sum of the voltages across each bulb.Chalf the sum of the voltages across each bulb.Dtwo times the sum of the voltages across each bulb.

Verified Answer :

Related Questions

In a series circuit, the voltage across the circuit is always equal to

Athe voltage across one of the bulbs.
Bthe sum of the voltages across each bulb.
Chalf the sum of the voltages across each bulb.
Dtwo times the sum of the voltages across each bulb.