angell1 angell1

21-03-2016
Physics

Answered

50 J of work was performed in 20 seconds. how much power was used to do this task?

Verified Answer :

21-03-2016

   Power = (amount of work done) / (time to do the work).

   = (50 J) / (20 sec)

   = 2.5 joule/sec = 2.5 watts .

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tddreviews tddreviews

26-10-2018

The Correct answer to this question for Penn Foster Students is: 2.5 W

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