A closed container has 3.06 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container?
The approximate total mass= number of atoms * weight of an atom.
The approximate total mass=3.06 10²³ atoms. (1.67 10⁻²⁴ grams/1 atom)=
=0.51102 g ≈ 0.51 g
Answer: the spproximate total mass is 0.51 grams.
Answer:
The approximate total mass, in grams is \(0.511\ grams\)
Step-by-step explanation:
we know that
To calculate the approximate total mass of all the atoms of the gas in the container, multiply the numbers of atoms by the weight of an atom
Let
x-------> the numbers of atoms
y------> the weight of an atom
m-----> the approximate total mass
\(m=xy\)
In this problem we have
\(x=3.06*10^{23}\ atoms\)
\(x=1.67*10^{-24}\ grams\)
substitute
\(m=(3.06*10^{23})(1.67*10^{-24})=5.1102*10^{-1}=0.511\ grams\)