Using calories, calculate how much heat 32.0 g of water absorbs when it is heated from 25.0 octo 80.0 °C. How many joules is this?
Answer:
Q = 1760 cal or 7356.8 J
Explanation:
The general expression to use to calculate heat is the following:
Q = mCpΔT (1)
Where:
Q = heat in cal or joules
m = mass of the compound.
Cp = specific heat of the compound
T: change in temperature (K) or T2 - T1
Now, the reported Cp for water is 1 cal/g °C and 4.18 J / g °C, we will use both to calculate the heat in calories and joules:
Using calories we have:
Q = 32 1 (80 - 25)
Q = 1760 cal
This is the heat in calories.
Using joules we have:
Q = 32 4.18 (80 - 25)
Q = 7356.8 J
This is the heat expressed in Joules.