Coulomb's Law:
\(F=\frac{kq_1q_2}{r^2}\)
k is a constant
q1 and q2 are charges
r is the distance
\(F_1=\frac{kq_1q_2}{r^2}\)
the distance is tripled:
\(F_2=\frac{kq_1q_2}{(3r)^2}=\frac{kq_1q_2}{9r^2}\)
\(\frac{\frac{kq_1q_2}{9r^2}}{\frac{kq_1q_2}{r^2}}= \frac{r^2}{9r^2}=\frac{1}{9}\)
The strength of the electrostatic repulsion will decrease by a factor of 9.
