Answer:
Given the polynomial: \((3x-8)(2x^2+4x-9)\)
Since, arranging of polynomial can be made by forming the given polynomial into the general form.
Multiply the following polynomials are;
\((3x)(2x^2+4x-9)-8(2x^2+4x-9))\)
Using distributive property: \(a\cdot(b+c) = a\cdot b+a\cdot c\)
\((6x^3+12x^2-27x)- (16x^2+32x -72)\)
Remove the parenthesis; we get;
\(6x^3+12x^2-27x- 16x^2 -32x +72\)
Combine like terms;
\(6x^3-4x^2-59x+72\)
⇒This is the general form of the polynomial equation.
Since, the given polynomials can be written from the order of powers i.e,
\(6x^3-4x^2-59x+72\)
To arrange this polynomial in descending order means to arrange the powers of variables in each term in descending order.
Therefore, the resulting polynomial in descending orders is, \(6x^3-4x^2-59x+72\)