Verified Answer :

There are 35 total animals and 5 parakeets and 15 dogs. 15/35100 is there percentage of dogs and 5/25100 is the percentage of parakeets. (15-5)/35*100 is the percentage difference. Simplifying, this equals 28.571%

Answer:  The required percentage is 28.57%.

Step-by-step explanation:  Given that at an animal shelter, there are 15 dogs, 12 cats, 3 snakes, and 5 parakeets.

We are to find the percentage by which parakeets are less than dogs.

From the given information, the number of dogs is

\(n_d=15,\)

the number of parakeets is

\(n_p=5.\)

And, the total number of animals is

\(n=15+1+3+5=35.\)

So, the difference of the number of dogs and parakeets is

\(N=n_d-n_p=15-5=10.\)

Therefore, the percentage by which parakeets are less than dogs is

\(\dfrac{N}{n}\times100\%=\dfrac{10}{35}\times100\%=\dfrac{200}{7}\%=28.57\%.\)

Thus, the required percentage is 28.57%.