A piece of art is in the shape of an equilateral triangle with sides of 6 in. Find the area of the piece of art. Round your answer to the nearest tenth

A12.7 in2
B15.6 in2
C31.2 in2
DNone of these

Verified Answer :

Area of equilateral triangle =   s²√3/4

Where s = length of side

s = 6

Area, A = s²√3/4 = 6²√3/4  = 36√3/4 = 9√3

A = 9√3 = 9
1.732 ≈ 15.588

A ≈ 15.6 in²   to the nearest tenth. (B)

Answer:

(B)\(15.6 in^2\)

Step-by-step explanation:

Given:  A piece of art is in the shape of an equilateral triangle with sides of 6 in.

To find: The area of the piece of art.

Solution: Since, the piece of art is in the shape of an equilateral triangle, thus the area of equilateral triangle=\(\frac{\sqrt{3}}{4}{\times}(side)^{2}\)

=\(\frac{\sqrt{3}}{4}{\times}(6)^2\)

=\(\frac{\sqrt{3}}{4}{\times}6{\times}6\)

=\(9\sqrt{3}\)

=\(9(1.732)\)

=\(15.6 in^2\)

Therefore, area of the piece of art=\(15.6 in^2\)