6d^2+33d+27, what is the answer?
\(6d^2+33d+27 \\ \\ GCF = 3 \\ \\ 3( \frac{6d^2}{3} + \frac{33d}{3} + \frac{27}{3} ) \\ \\ 3(2d^2 + 11d + 9) \\ \\ 3(2d^2 + 9d + 2d + 9) \\ \\ 3(d(2d + 9) + (2d + 9)) \\ \\ 3(2d + 9)(d + 1) \\ \\\)The final result is: 3(2d + 9)(d + 1)
