Choose the product. a 2b 3 · 6ab 2
Let's reorganize the problem to make it easier to understand... we can change the order because of the commutative property of multiplication.(3)2ab (2)6ab=6ab 12ab=72 a^2b^2
Answer:
\(6(a^{3})(b^{5})\)
Step-by-step explanation:
we have
\(a^{2}b^{3}6ab^{2}\)
Group terms that contain the same variable
\(6(a^{2}a)(b^{3}b^{2})\)
sum the power
\(6(a^{2+1})(b^{3+2})\)
