LucyNeedsMathHelp
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Nick is solving the equation \[3x^2 = 20 - 7x\] with the quadratic formula.


What values should he use for a, b, and c?



Aa = 3

b = 20

c = -7


Ba = 3

b = -7

c = 20


Ca = 3

b = 7

c = -20


Da = 3

b = -20

c = 7

Verified Answer :

Cupcake164

Okay so we know that the equation for the quadratic formula is x = -b+/- (sqr) b^2 - 4ac.
Well the way to plug the numbers in is by using this equation: Ax^2 + Bx + C = 0 :)
S if you use your equation : 3x^2 = 20 - 7x
First you have to move everything to one side.
So it'll look like this:
3x^2 = 20 - 7x
-20      -20
3x^2 - 20 = -7x
+7x             +7x
3x^2 - 20 + 7x = 0
So remember Ax^2 +Bx+ C= 0
3 = A
7 = B
-20 = C
So the answer is C :)

Answer:

Option C is correct.

a = 3

b = 7

c -20

Step-by-step explanation:

A quadratic equation is in the form of :

\(ax^2+bx+c=0\)           ....[1]

where a, b and c are coefficient and x is the variable term.

As per the statement:

Nick is solving the equation \(3x^2 = 20 -7x\) with the quadratic formula.

Given the equation:

\(3x^2 = 20 -7x\)

Add 7x to both sides we have;

\(3x^2 +7x= 20\)

Subtract 20 from both sides we have;

\(3x^2 +7x -20=0\)

On comparing with equation [1] we have;

a = 3, b = 7 and c =  -20

Therefore, the values of a, b and c are:

a = 3

b = 7

c -20

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