Verified Answer :

Answer:The heat absorbed by the 20 g of ice is 6,680 Joules.

Explanation:

Enthalpy of fusion is defined as amount of heat required to change the 1 mole of substance from solid phase to liquid phase  when pressure and temperature remains constant.

Here in the question we are given with an enthalpy of fusion of 334 J/g. Which means that 334 Joules of heat will be required to melt 1 gram of ice.

Mass of ice in calorimeter = 20 g

Heat absorbed by the 20 g of ice =\(20 g\times 334 J\g=6,680 J\)

Eduard22sly

The amount of heat energy absorbed by the 20 g of ice in the calorimeter is 6680 J

Data obtained from the question

From the question given above, the following data were obtained:

  • Mass of ice = 20 g
  • Heat of fusion (ΔHf) = 334 J/g
  • Heat (Q) =?

How to determine the heat absorbed

The heat absorbed can be obtained as illustrated below:

Q = m × ΔHf

Q = 20 × 334

Q = 6680 J

Learn more about heat transfer:

https://brainly.com/question/6363778

Related Questions