The total length of the frogs three jumps was 2.25 m
Further explanation
Some units of length and its conversion that need to be recalled are:
\(1 ~ foot = 30.48 ~ cm\)
\(1 ~ inch = 2.54 ~ cm\)
\(1 ~ foot = 12 ~ inches\)
\(1 ~ mile = 1609.34 ~ metres\)
\(1 ~ yard = 0,9144 ~ metres\)
\(1 ~\mu m = 1 \times 10^{-6} ~ m\)
\(1 ~ \text{US liquid gallon} = 3.78541 ~ litres\)
Some units of time and its conversion that need to be recalled are:
\(1 ~ month = 30 ~ days\)
\(1 ~ day = 24 ~ hours\)
\(1 ~ hour = 60 ~ minutes\)
\(1 ~ minute = 60 ~ seconds\)
Let us now tackle the problem !
Given:
distance of first jump = d₁ = 1 meter
distance of second jump = d₂ = 85 centimeters
distance of third jump = d₃ = 400 millimeters
Unknown:
total distance = d = ?
Solution:
This problem is about conversion unit of length.
We have to recall that :
\(\boxed {1 \ m = 100 ~ cm}\)
\(\boxed {1 \ m = 1000 ~ mm}\)
\(\text{Total Distance} = d = d_1 + d_2 + d_3\)
\(d = 1 ~ m + 85 ~ cm + 400 ~ mm\)
\(d = 1 ~ m + \frac{85}{100} ~ m + \frac{400}{1000} ~ m\)
\(d = 1 ~ m + 0.85 ~ m + 0.4 ~ m\)
\(d = 2.25 ~m\)
Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
Answer details
Grade: High School
Subject: Mathematics
Chapter: Unit of Length
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Length , Microscope , Gallons , Month , Liters , Hour , Time, Frog , Jump
