If we count, there are 15 values, so we just have to find the middle one, which is 21
The median of the first problem is 21.
Mode = The number that occurs most frequently in the set. In this set, we can see that the number 22 appears 4 times, which is more than any other number in the set.
22 is the mode for the first problem.
Range = The distance in numeric value between the highest number of the set and the lowest number.
26 is the highest number and 17 is the lowest.
26 - 17 = 9
The range of the first problem is 9.
2. We solve for average by adding all values together and then dividing by the amount of values there are.
The average amount of grain needed is \(21 \frac{2}{15}\)
3. For this one, we just have to solve it the same way, and then compare the central measures.
Median = 21 (For this one, there was an even amount of numbers, so we just took the average of the two closest to the middle, both of which were 21. The average of two numbers of the same value is that same number)
Mode = 22
Range = 9
The three values have not changed from the original values, so there is no change.
