we have
\(y=7x^{2}-10\)
To find the inverse
Step 1
Exchanges the variables, x for y and y for x
\(x=7y^{2}-10\)
Step 2
Isolate the variable y
\(x=7y^{2}-10\)
\(7y^{2}=x+10\)
\(y^{2}= \frac{x+10}{7}\)
Square Root both sides
\(y=(+/-)\sqrt{\frac{x+10}{7}}\)
Step 3
Let
\(f(x)^{-1}=y\)
so
\(f(x)^{-1}=(+/-)\sqrt{\frac{x+10}{7}}\)
therefore
the answer is
The inverse is
\(f(x)^{-1}=(+/-)\sqrt{\frac{x+10}{7}}\)
