sin=opposite / hypotenuse
cos=adjacent / hypotenuse
tan=opposite / adjacent
Sin of A= opposite / hypotenuse
= 4 (sides of the right triangle are congruent, it's an isoscles) / \(4* \sqrt{2}\)
= 1/ \(\sqrt{2}\)
= \(\sqrt{2} / 2\)
Cos of A= adjacent / hypotenuse
= 4 / \(4* \sqrt{2}\)
= 1/ square root of 2
= \(\sqrt{2} / 2\)
Tan of A=opposite / adjacent
= 4/4
= 1
Hope this helps :)
