If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, what is the volume of the tank? Assume 3.14 for pi. A) 28.3 m3 B) 37.7 m3 C) 56.5 m3 Eliminate D) 84.8 m3
For a cylindrical tank, volume = πr²h
Where r = radius = diameter/2 = 6/2 = 3m
height , h = 3m
Volume = 3.14 3² 3 = 84.78
Volume ≈ 84.8 m³
Option D.
Answer:
(D) \(V\)≈\(84.8m^3\)
Step-by-step explanation:
It is given that If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, thus the radius of the cylindrical tank is given as:
\(Diameter=\frac{Radius}{2}=\frac{6}{2}=3m\)
and the height is=6m.
Now, the volume of the cylindrical tank is given as:
\(V={\pi}r^2h\)
Substituting the given values, we get
\(V=3.14(3)^2(3)\)
\(V=3.14(27)\)
\(V=84.78m^3\)
\(V\)≈\(84.8m^3\)
Hence, the volume of the cylindrical tank is \(84.8m^3\).
Thus, option D is correct.