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If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, what is the volume of the tank? Assume 3.14 for pi. A) 28.3 m3 B) 37.7 m3 C) 56.5 m3 Eliminate D) 84.8 m3

Verified Answer :

For a cylindrical tank, volume = πr²h

Where r = radius = diameter/2 = 6/2 = 3m
height , h = 3m

Volume  =  3.14 3² 3 = 84.78

Volume ≈ 84.8 m³

Option D.

Answer:

(D) \(V\)≈\(84.8m^3\)

Step-by-step explanation:

It is given that If a plant manufacturing carpet backing has a cylindrical tank that is 3 meters high and is 6 meters in diameter, thus the radius of the cylindrical tank is given as:

\(Diameter=\frac{Radius}{2}=\frac{6}{2}=3m\)

and the height is=6m.

Now, the volume of the cylindrical tank is given as:

\(V={\pi}r^2h\)

Substituting the given values, we get

\(V=3.14(3)^2(3)\)

\(V=3.14(27)\)

\(V=84.78m^3\)

\(V\)≈\(84.8m^3\)

Hence, the volume of the cylindrical tank is \(84.8m^3\).

Thus, option D is correct.