Answer: \(\dfrac{1}{4}\)
Step-by-step explanation:
Given : There are 12 pieces of fruit in a bowl.
Seven of the pieces are apples and two are peaches.
i.e. The combined number of pieces of apples and peaches =7+2=9
Pieces of fruit are neither apple nor peach = 12-9=3
Now, the probability that a randomly selected piece of fruit will not be an apple or a peach will be :-
\(=\dfrac{\text{Total number of pieces are not either apples or peach}}{\text{Total pieces of fruits}}\\\\=\dfrac{3}{12}\\\\=\dfrac{1}{4}\)
Hence, the probability thaat a randomly selected piece of fruit will not be an apple or a peach= \(\dfrac{1}{4}\)
