Easy,
now it looks tricky but it's not,
you're trying to find the Area of the circle, but you don't have the radius.
What you do have is a triangle with two sides labeled \(\sqrt{2}\)
Now, using Pythagorean Theorem:
\(a ^{2}+ b^{2}= c^{2}\)
\(\sqrt{2} ^{2} + \sqrt{2} ^{2}= c^{2}\)
But we know that the OPPOSITE of square root is squared.
Making it,
2+2=\(c^{2}\)
4=\(c^{2}\)
2=c
The third side is 2. (Diameter) As the radius, 1.
Now, to find the Area of a Circle,
A=\(\pi\)\(r^{2}\)
A=\(\pi *1\)
Making your answer, 3.14 sq cm, A.
