A bus slams on its breaks and goes from 30 km/hr to 15km/hr in 4 seconds. What is its acceleration?
\(Formula\ for\ acceleration:\\\\ a=\frac{v_2-v_1}{t}\\\\ v_1=30km\hr\\v_2=15km\hr\\t=4s\\\\ a=\frac{15-30}{4}=\frac{-15}{4}=-3,75\frac{km}{s^2}\\\\Acceleration\ is\ equal\ to\ 3,75{km}{s^2}. \\Bus\ is\ deccelerating.\)
Acceleration is the rate of change of speed.
If the speed is increased then its called acceleration
If the speed is decresed then its a negative acceleration also called deceleration
the formula for calculating acceleration is
\(a = \frac{v-u}{t}\)
where a - acceleration
v - final velocity
u - initial velocity
t - time
v - 15 km/hr should be converted to m/s
distance in 1 hour - 15 km
1 hour = 3600 s
1 km - 1000 m
in 3600 s - 15 000 m
in 1 s - 15 000 m / 3600 s = 4.17 m/s
u - 30 km/hr
in 3600 s - 30 000 m
in 1 s - 30 000 m / 3600 s = 8.33 m/s
substituting the values in the equation
\(a = \frac{4.17 m/s - 8.33 m/s}{4 s} = \frac{-4.16}{4}\) = -1.04 m/s²
the answer is negative means its deceleration
the acceleration is -1.04 m/s²