Answer : His acceleration from 5 s to 10 s will be, \(0.8m/s^2\)
Solution : Given,
Initial velocity = 3 m/s
Final velocity = 7 m/s
Initial time = 5 s
Final time = 10 s
Acceleration : Acceleration is defined as the rate of change of velocity with respect to the time taken.
Formula used :
\(a=\frac{\Delta V}{\Delta t}\\\\a=\frac{V_{final}-V_{initial}}{t_{final}-t_{initial}}\)
where,
a = acceleration
\(\Delta V\) = change in velocity
\(\Delta t\) = change in time
Now we have to calculate the acceleration from 5 s to 10 s :
Put all the given values in the above formula, we get
\(a=\frac{V_{final}-V_{initial}}{t_{final}-t_{initial}}\)
\(a=\frac{7m/s-3m/s}{10s-5s}=0.8m/s^2\)
Therefore, his acceleration from 5 s to 10 s will be, \(0.8m/s^2\)
