Answer:
The point slope form of the line is \(y-8=-\frac{2}{3}(x+3)\).
Step-by-step explanation:
The slope intercept form of a line is
\(y=mx+b\) .... (1)
where, m is slope and b is y-intercept.
The given equation is
\(y=-\frac{2}{3}x+6\) .... (2)
From (1) and (2) it is clear that
\(m=-\frac{2}{3},b=6\)
The slope of the line is \(-\frac{2}{3}\).
The point slope form of a line is
\(y-y_1=m(x-x_1)\)
Where, m is slope.
The slope of the line is \(-\frac{2}{3}\) and it passes through the point (-3,8).
\(y-8=-\frac{2}{3}(x-(-3))\)
\(y-8=-\frac{2}{3}(x+3)\)
Therefore the point slope form of the line is \(y-8=-\frac{2}{3}(x+3)\).
