Verified Answer :

707863128

The answer will be .04\(x^{2}\) -0.2xy+0.25\(y^{2}\) 

using the formula  \(a^{2} -2ab + b^{2}\)

apologiabiology

I thnk you means exand

so
(0.2x-0.5y)^2=(0.2x-0.5y)(0.2x-0.5y)

use distributive prpoety
a(b+c)=ab+ac
so
(0.2x-0.5y)(0.2x-0.5y)=(0.2x-0.5y)(0.2x)+(0.2x-0.5y)(-0.5y)=(0.2x)(0.2x)+(-0.5y)(0.2x)+(0.2x)(-0.5y)+(-0.5y)(-0.5y)=0.4x^2-0.2xy+0.25y^2



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