Answer:
The required value of x = 28
The required value of y = 32
Step-by-step explanation:
The given two equations are :
\(\frac{3}{4}(x-12)=12..........(1)\\\\\frac{3}{4}\cdot y-12=12...........(2)\)
Now, we need to solve both the equations and find out the required values of both the unknowns x and y.
Solving equation (1) to obtain value of x. We have,
\(\frac{3}{4}(x-12)=12\\\\\text{On cross multiplication, we get}\\\\\implies 3\times (x-12)=12\times 4\\\implies 3x -36=48\\\implies 3x=48+36\\\implies 3x=84\\\bf\implies x=28\)
Solving equation (2) to obtain value of y. We have,
\(\frac{3}{4}\cdot y-12=12\\\\\implies \frac{3}{4}\cdot y=12+12\\\\\implies \frac{3}{4}\cdot y=24\\\\\text{On cross multiplicatrion, We get}\\\implies 3\cdot y=24\times 4\\\implies 3y = 96\\\bf\implies y=32\)
Hence, The required value of x = 28
And The value of y = 32
