1/4(12x+16)=10-3(x-2) anyone?
\(\frac{1}{4}(12x+16)=10-3(x-2)\\\\3x+4=10-3x+6\\\\3x+4=16-3x\ \ \ \ \ \ |subtract\ 4\ from\ both\ sides\\\\3x=12-3x\ \ \ \ \ \ \ |add\ 3x\ to\ both\ sides\\\\6x=12\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 6\\\\\boxed{x=2}\)
