q(a+y)=67y+93 solve for y
\(Q(a+y)=67y+93\\ aQ+Qy=67y+93\\ Qy-67y=-aQ+93\\ y(Q-67)=-aQ+93\\ y=\dfrac{-aQ+93}{Q-67}\\ \boxed{y=-\dfrac{aQ-93}{Q-67}}\)
Answer:
y=93-aq/q-6
Step-by-step explanation:
