What are the solutions to 4x^2 +25=0
\(\sqrt{x} \sqrt{x} -25/4 no real solution\)Subtract 25 from both sides
4x^2+25-25 = 0-25
4x^2= -25
Divide both sides by 4
4x^2/4=-25/4
x^2= -25/4
Take square root
x+- square root -25/4
No solution .
I hope that's help.
