Verified Answer :

\(x^2 - 5x - 14=\\ x^2+2x-7x-14=\\ x(x+2)-7(x+2)=\\ (x-7)(x+2)\)

Answer:

The factors are \((x-7)\)  and  \((x+2)\)

Step-by-step explanation:

we have

\(x^{2} -5x-14\)

To find the factors equate the equation to zero

\(x^{2} -5x-14=0\)

Group terms that contain the same variable, and move the constant to the opposite side of the equation

\(x^{2} -5x=14\)

Complete the square. Remember to balance the equation by adding the same constants to each side

\(x^{2} -5x+6.25=14+6.25\)

\(x^{2} -5x+6.25=20.25\)

Rewrite as perfect squares

\((x-2.5)^{2}=20.25\)

\((x-2.5)=(+/-)\sqrt{20.25}\)

\((x-2.5)=(+/-)4.5\)

\(x=2.5(+/-)4.5\)

\(x=2.5+4.5=7\)

\(x=2.5-4.5=-2\)

therefore

\(x^{2} -5x-14=(x-7)(x+2)\)

using a graphing tool see the attached figure

The factors of the quadratic equation are the x-intercepts (values of x when the value of the function is equal to zero)

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