We will use simple formula for velocity with constant acceleration.
\(v=v0+at\) and formula for path \(x=x0+v0t+ \frac{1}{2}a t^{2}\)
where:
v0 - initial velocity
a - constant acceleration
t- time
x - path
x0 - initial position
v0, and x0 are equal to 0 in this case, so we can simplify our formula to
\(v=at\) and \(x= \frac{1}{2}a t^{2}\)
We can modify first formula to get time
\(t= \frac{v}{a}\) and substitute it to second formula.
\(x= \frac{1}{2}*a \frac{ v^{2}}{ a^{2} } = \frac{1}{2} \frac{ v^{2} }{a}\)
Now we can find acceleration
\(a= \frac{1}{2} \frac{ v^{2} }{x} =2.27\) m/s