How do I solve c/4d divided by 3/8d
\(\frac{c}{4d}:\frac{3}{8d}=\frac{c}{4d}\times\frac{8d}{3}=\boxed{\frac{2c}{3}}\)
\(\frac{c}{4d}: \frac{3 }{8d}=\frac{c}{4d} \cdot \frac{8d}{3 }= \frac{2c}{3}\\\\d eq0\)
