2300 student athletes signed up for a spring sport in 2012.
Given,
Student athletes competing in spring sport in 2014 is 2277.
Let there were x students competing in year 2013.
According to the question,2277 was 110% of the number of students competing in 2013. So,
\(110\ \% \ \rm of \ x= 2277\)
\(\dfrac{110}{100} \times \rm x=2277\)
\(\rm x=\dfrac{2277\times 100}{110}\)
\(\rm x=2070\)
Hence 2070 students competing in year 2013.
Let the student competing in 2012 be y.
Now, 2070 was 90% of the number of students competing in year 2012.
So,
\(90\%\ \rm of \ y= 2070\)
\(\dfrac{90}{100} \times \rm y=2070\\\)
\(\rm y=\dfrac{2070\times 100}{90}\)
\(\rm y=2300\)
Hence the students competing in year 2012 was 2300.
For more details on percentage calculation follow the link:
https://brainly.com/question/8011401
