Question: One third of a number, decreased by thirty-six is at most twenty-two.
First write it out.
1/3x - 36 ≥ 22
Add 36 to both sides
1/3x ≥ 58
divide both sides by 1/3, and you get 174
the number: x
one third of the number: \(\frac13x\)
decreased 36: -36
at most means equal or less: ≤
So, we get: \(\frac13x-36\leq22\)
add 36 to both sides: \(\frac13x-36+36\leq22+36\)
\(\frac13x\leq58\)
Multiply both sides by 3: \(3\cdot\frac13x\leq3\cdot58\)
\(~\ \ \ x\leq 174\\\\ x\in(-\infty\ ;\ 174\ \textgreater\)