Easy, there are two methods,
Method One, combine the two common factors of 13-2x by adding the exponents. Making the answer,
(13-2\(x)^{2}\)
The other method is by multiplying it out, using FOIL (First, Outer, Inner, Last)
switch
(13-2x)(13-2x)
to
(-2x+13)(-2x+13) now you can multiply,
take, FIRST, -2x-2x
=\(4x^{2}\)
then, OUTER, -2x13
=-26x
then, INNER, 13-2x
=-26x
finally, LAST, 1313
=169
Finally, add, the sum together.
4\(x^{2}\)-26x-26x+169
4\(x^{2}\)-52x+169.
This, is your answer.
