Answer:
the value of \(f(g(4))\) is, 13
Step-by-step explanation:
Given the function:
\(f(x) = x-3\)
\(g(x) = x^2\)
we have to find the value of \(f(g(4))\);
\(f(g(x)) = f(x^2)\)
Replace x in place of \(x^2\) in the fucntion f(x) we have;
\(f(g(x)) =f(x^2) = x^2-3\)
⇒\(f(g(x)) = x^2-3\)
Put x = 4 we have;
\(f(g(4)) = 4^2-3=16-3 =13\)
Therefore, the value of \(f(g(4))\) is, 13